题目:设int a; 则表达式(a=2,3),a+1的值
- #include<stdio.h>
- int main(void)
- {
- int a=0;
- int b;
- int c;
- b = (a=2,4);
- c = (a=2,3),a+1;
- printf("a+1=%d\n",a+1); //a+1 = 3;
- printf("a=2,4的值为:%d\n",b); //a=2,4的值为:4
- printf("(a=2,3),a+1的值为:%d\n",c); //(a=2,3),a+1的值为:3
- return 0;
- }
