If
R
R
R is a rectangular matrix, then
N
=
R
T
∗
R
N=R^T*R
N=RT∗R must be a symmetric matrix. Why?
What are the different types of vector space in general?
What are the basic rules that a vector space have to follow?
What are the properties that a vector in
R
n
\mathbb{R}^n
Rn have? (Hint: dimension of vectors & value type of each components)
List all the possible subspaces of
R
n
\mathbb{R}^n
Rn
What’s the differences between
R
2
\mathbb{R}^{2}
R2 and a subspace (plane) of
R
n
\mathbb{R}^n
Rn
List the vector sets of
l
i
n
e
1
:
y
=
x
,
l
i
n
e
2
:
y
=
−
x
+
1
line1:y=x,line2:y=-x+1
line1:y=x,line2:y=−x+1 in
R
2
\mathbb{R}^2
R2 (lines go through the origin or not)
What’s the differences between a line and a vector in
R
n
\mathbb{R}^n
Rn
Why the subspaces of
R
n
\mathbb{R}^n
Rn like line/plane… have to go through the origin? (Hint: relate to Q7&Q8)
Given matrix
A
m
∗
n
A_{m*n}
Am∗n, how to determine
C
(
A
)
C(A)
C(A) ? (Hint: definition of
C
(
A
)
C(A)
C(A))
What’s the relationship between
C
(
A
)
C(A)
C(A) and
R
m
,
R
n
\mathbb{R}^m, \mathbb{R}^n
Rm,Rn ?
Answer
When talking about symmetry, the first thing need to pop out is
A
T
=
A
A^T=A
AT=A. We apply this formula to
R
T
R
R^TR
RTR,
(
R
T
R
)
T
=
R
T
(
R
T
)
T
=
R
T
R
(R^TR)^T=R^T(R^T)^T=R^TR
(RTR)T=RT(RT)T=RTR. Hence,
R
T
R
R^TR
RTR is symmetric.
“vector” can be couple of things:
vector space
matrix space →
M
\mathbb{M}
M
function space →
F
\mathbb{F}
F
zero space →
Z
\mathbb{Z}
Z
If we take any 2 vectors from vector space
S
S
S, then
x
3
=
c
1
x
1
+
c
2
x
2
x_3=c_1x_1+c_2x_2
x3=c1x1+c2x2 (
c
1
,
c
2
c_1,c_2
c1,c2 are scalars) is still in that space
every vector in
R
n
\mathbb {R}^n
Rn has
n
n
n components, and the value type of each components is real number (That’s where letter R come from)
here are all the possibilities:
zero vector with n components
Any line / plane … through the origin
R
n
\mathbb{R} ^n
Rn
The number of components each vector has is different
here are the 2 vector set of lines in
R
2
\mathbb {R}^2
R2
l
i
n
e
1
:
y
=
x
→
(
(
0
,
0
)
,
(
1
,
1
)
,
(
−
1
,
−
1
)
)
,
…
line1:y=x \to ((0,0),(1,1),(-1,-1)),\dots
line1:y=x→((0,0),(1,1),(−1,−1)),…
l
i
n
e
2
:
y
=
−
x
+
1
→
(
(
0
,
1
)
,
(
1
,
0
)
,
(
0.5
,
0.5
)
)
line2:y=-x+1 \to ((0,1),(1,0),(0.5,0.5))
line2:y=−x+1→((0,1),(1,0),(0.5,0.5))
a vector is formed by an arrow and a point, a line is formed by points of vectors
here is the explanation:
Take 2 vectors
v
1
,
v
2
v_1,v_2
v1,v2 in
l
i
n
e
2
:
y
=
−
x
+
1
line2:y=-x+1
line2:y=−x+1, their linear combination
v
3
=
c
1
v
1
+
c
2
v
2
v_3=c_1v_1+c_2v_2
v3=c1v1+c2v2 is not always in that vector set, and zero vector is also not in that space, so this line is not a subspace
When it turns into
l
i
n
e
1
:
y
=
x
line1:y=x
line1:y=x, the definition of subspace is satisfied, so does other lines that go through the origin. Therefore, we say that subspaces have to go through the origin
We do elimination to
A
A
A to get pivot columns, and span
C
(
A
)
C(A)
C(A) by those pivot columns
C
(
A
)
C(A)
C(A) is a subspace of
R
m
\mathbb {R}^m
Rm