力扣算法题：将数字变为0的操作次数--多语言实现

无意间看到，力扣存算法代码居然还得升级vip。。。好吧，我自己存吧

golang：

func numberOfSteps(num int) int {
    steps := 0
	for num > 0 {
		if num%2 == 0 {
			num /= 2
		} else {
			num -= 1
		}
		steps++
	}
	return steps
}

javascript:

/**
 * @param {number} num
 * @return {number}
 */
var numberOfSteps = function(num) {
    let step = 0;
    while(num > 0){
        if (num % 2 === 0) {
            num /= 2
        } else {
            num -= 1
        }
        step++
    }
    return step     
};

python:

class Solution(object):
    def numberOfSteps(self, num):
        """
        :type num: int
        :rtype: int
        """
        step = 0
        while num > 0:
            if num % 2 == 0:
                num //= 2
            else:
                num -= 1
            step += 1
        return step