
- package 蓝桥杯国赛;
- // 贪心选个数最少的进行摆
- // 2:1 ,3:1, 4:1,5 : 3,6:3,7:1
- // 选 1,7,4,2,3,5,9
- // 然后都选满10个
- public class 火彩棒数字 {
- public static void main(String[] args)
- {
- System.out.print("9999999999777777777755555555554444444444333333333322222222221111111111");
- }
- }

- package 蓝桥杯国赛;
- import java.util.Scanner;
- //1:无需package
- //2: 类名必须Main, 不可修改
- //C28 * f[i] 错排公式
-
- //f[i] = (i - 1) (f[i - 1] + f[i - 2])
-
- public class 小蓝与钥匙 {
- static int N = 100;
- static long[] f = new long[N];
- public static void main(String[] args) {
- long ans = 1;
- f[2] = 1;
- for(int i = 3;i < N;i++)
- f[i] = (i - 1) * (f[i - 1] + f[i - 2]);
- for(long i = 0;i < 14;i++)
- ans = ans * (28 - i) / (i + 1);
- System.out.println(ans * f[14]);
- }
- }

package 蓝桥杯国赛; import java.util.Scanner; public class 内存空间 { public static void main(String[] args) { Scanner in=new Scanner(System.in); int t=in.nextInt(); long sum=0; in.nextLine(); while(t-->0){ String []s=in.nextLine().split(" "); if(s[0].equals("int")){ String[]s1=s[1].split(","); sum+=4*s1.length; }else if(s[0].equals("long")){ String[]s1=s[1].split(","); sum+=8*s1.length; }else if(s[0].equals("String")){ String[]s1=s[1].split(","); for(String ss:s1){ int index=ss.indexOf("\""); int tmp=ss.indexOf("\"",index+1)-index-1; sum+=tmp; } }else if(s[0].equals("int[]")) { for(int i=2;i int l=s[i].indexOf("["); int r=s[i].indexOf("]"); int tmp=Integer.parseInt(s[i].substring(l+1,r)); sum+=4*tmp; } }else if(s[0].equals("long[]")) { for(int i=2;i int l=s[i].indexOf("["); int r=s[i].indexOf("]"); int tmp=Integer.parseInt(s[i].substring(l+1,r)); sum+=8*tmp; } } } long gb,mb,kb,k; gb=sum/1024/1024/1024; mb=sum%(1024*1024*1024)/1024/1024; kb=sum%(1024*1024)/1024; k=sum%1024; String res=""; if (gb != 0) res += gb + "GB"; if (mb != 0) res += mb + "MB"; if (kb != 0) res += kb + "KB"; if (k != 0) res += k + "B"; System.out.println(res); } }
package 蓝桥杯国赛; import java.util.Scanner; // 由之前算出当n > 30 f[] > 1e6 public class 斐波那契数组 { static int N = 100100; static int[] f = new int[N],a = new int[N]; public static void main(String[] args) { f[1] = 1;f[2] = 1; for(int i = 3;i <= 30;i++) f[i] = f[i - 1] + f[i - 2]; Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); for(int i = 1;i <= n;i++) a[i] = scanner.nextInt(); int ans = 0,m = n; if(n > 30) n = 30; for(int i = 1;i <= n;i++) { int cnt = 0; if(a[i] % f[i] == 0) { int t = a[i] / f[i]; for(int j = 1;j <= n;j++) if(f[j] * t == a[j]) cnt++; ans = Math.max(ans,cnt); } } System.out.print(m - ans); } }
package 蓝桥杯国赛; import java.util.*; // 特殊的dijkstra // dijkstra是每个选取最小的,如果弹出的节点已径扩展过了,就continue // 然后扩展每个点计算经过该点的最短路径,如果小于就原最短路径,则入堆 // 这里特殊的边权值是动态变化的 // tt < g 则当前路口为绿灯 // g < tt < g + d 则当前路口为黄灯且下一个灯为红灯 // g + d < tt < g + d + r 则当前路口为红灯 // g + d + r < tt < g + 2d + r 则当前路口为黄灯且下一个灯为绿灯 public class 交通信号 { static final int N = 1000010, M = 4 * N; static int[] h = new int[N], e = new int[M], ne = new int[M], g = new int[M], r = new int[M], d = new int[M], f = new int[M]; static long[] times = new long[N]; static int idx = 0; static void add(int a, int b, int green, int red, int dist, int flag) { e[idx] = b; g[idx] = green; r[idx] = red; d[idx] = dist; ne[idx] = h[a]; f[idx] = flag; h[a] = idx++; } static long dijkstra(int n, int m, int s, int t) { Arrays.fill(times, Long.MAX_VALUE); times[s] = 0; PriorityQueuepq = new PriorityQueue<>((a,b) -> Long.compare(a.dist,b.dist)); pq.offer(new Pair(s, 0)); while (!pq.isEmpty()) { Pair pair = pq.poll(); int u = pair.node; long dist = pair.dist; if (dist > times[u]) continue; for (int i = h[u]; i != -1; i = ne[i]) { int j = e[i]; long gr = g[i], re = r[i], di = d[i], fl = f[i]; long tot = gr + re + 2 * di; long curt = dist % tot; if (fl == 1) curt = curt >= gr ? tot - curt : 0; else curt = curt >= gr + di && curt < gr + di + re ? 0 : curt < gr + di ? gr + di - curt : tot - curt + gr + di; long newDist = dist + curt + di; if (newDist < times[j]) { times[j] = newDist; pq.offer(new Pair(j, newDist)); } } } return times[t] > Long.MAX_VALUE / 2 ? -1 : times[t]; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(),m = scanner.nextInt(); int s = scanner.nextInt(),t = scanner.nextInt(); Arrays.fill(h, -1); for (int i = 0; i < m; i++) { int a = scanner.nextInt(), b = scanner.nextInt(); int green = scanner.nextInt(),red = scanner.nextInt(); int dist = scanner.nextInt(); add(a, b, green, red, dist, 1); add(b, a, green, red, dist, 0); } System.out.println(dijkstra(n, m, s, t)); } static class Pair { private final int node; private final long dist; public Pair(int node, long dist) { this.node = node; this.dist = dist; } } }
import java.util.*; public class Main { static final int MAXV = 10; static final int mod = 1000000007; static int solve(int[] B, int N) { int[][][] f = new int[2][MAXV][MAXV]; int cur = 0, ans = 0; for (int i0 = 0; i0 < MAXV; ++i0) { for (int i1 = 0; i1 < MAXV; ++i1) { cur = 0; Arrays.stream(f[cur]).forEach(arr -> Arrays.fill(arr, 0)); f[cur][i0][i1] = 1; for (int i = 2; i < N; i++) { cur ^= 1; Arrays.stream(f[cur]).forEach(arr -> Arrays.fill(arr, 0)); for (int A0 = 0, prev = cur ^ 1; A0 < MAXV; ++A0) { for (int A1 = 0; A1 < MAXV; ++A1) { if (f[prev][A0][A1] == 0) continue; for (int A2 = 0; A2 < MAXV; ++A2) { if (Math.max(Math.max(A0, A1), A2) != B[i - 1]) continue; if (i == N - 1) { if (Math.max(Math.max(A1, A2), i0) != B[i] || Math.max(Math.max(i0, i1), A2) != B[0]) continue; } f[cur][A1][A2] += f[cur ^ 1][A0][A1]; f[cur][A1][A2] %= mod; } } } } for (int A0 = 0; A0 < MAXV; ++A0) { for (int A1 = 0; A1 < MAXV; ++A1) { ans += f[cur][A0][A1]; ans %= mod; } } } } return ans; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int N = scanner.nextInt(); int[] B = new int[N]; for (int i = 0; i < N; ++i) { B[i] = scanner.nextInt(); } System.out.println(solve(B, N)); } }
package 蓝桥杯国赛; import java.util.*; //本题使用bigInteger会超时 //可以利用位运算找规律 //1 //121 //12321 //1234321 //123454321 //12345654321 //一共有2n-1位, // 当i <= n 时 // 从右往左第i行,这一行有n - i + 1个 i,上面是i - 2,i - 4,.... 2(或1) // 这一位是[(n - i + 1) * i + k] k = i/2*(i - 2)/2 或 k = (i-1) / 2*(i - 1)/2 // 当 i > n 时 // 末尾为奇数时对1到末尾相加,为偶数时0 到 n 相加 public class 六六大顺 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); long n = scanner.nextLong(); StringBuilder x = new StringBuilder(); long carry = 0, t; for (long i = 1; i <= n; i++) { t = (n - i + 1) * i; if (i % 2 == 0) t += i * (i - 2) / 4; else t += (i - 1) * (i - 1) / 4; t = t * 36 + carry; x.append(t % 10); carry = t / 10; } for (long i = n + 1; i < 2 * n; i++) { long last_value = 2 * n - i; long cnt = (last_value + 1) / 2; if (i % 2 == 0) t = (last_value + 2) * cnt / 2; else t = (last_value + 1) * cnt / 2; t = t * 36 + carry; x.append(t % 10); carry = t / 10; } x.append(carry); System.out.println(x.reverse().toString()); } }
package 蓝桥杯国赛; import java.util.Scanner; //x的上一层的取值范围y 为 12 ~ 22,且为合数 //当y 为 12 :9 ~ 12 //当y 为 14 :14 - 7 + 1 = 8 //当y 为 15 :15 - 5 + 1 = 9 // ···· // 第一步求x 最大素数 z(如果是质数,就-1) // y的取之范围为 (x - z + 1, x ),y为合数 // 然后在求区间中➖最大素数 + 1 最大的数 public class 选素数 { static boolean is_prime(int n) { if(n <= 1) return false; for(int i = 2;i <= n / i;i++) if(n % i == 0) return false; return true; } static int lpf(int n) { int ans = 2; for(int i = 2; i <= n/i;i++) { while(n % i == 0) { ans = i; n /= i; } } return ans; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int x = scanner.nextInt(); if(is_prime(x)) { System.out.println(-1); }else { int z = lpf(x); int l = x - z + 1; int ans = (int)2e6; for(int i = l;i <= x;i++) { if(is_prime(i)) continue; ans = Math.min(ans,i - lpf(i) + 1); } System.out.println(ans); } } }国赛ac难度是大于省赛的,最后俩题放弃了
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- 原文地址:https://blog.csdn.net/weixin_61197809/article/details/138550023