做作业的时候,邻座的小盆友问你:“五乘以七等于多少?”你应该不失礼貌地围笑着告诉他:“五十三。”本题就要求你,对任何一对给定的正整数,倒着输出它们的乘积。

输入在第一行给出两个不超过 1000 的正整数 A 和 B,其间以空格分隔。
在一行中倒着输出 A 和 B 的乘积。
5 7
53
C:
- #include
- int main()
- {
- int a,b,n;
- int A,count=0;
- scanf("%d %d",&a,&b);
- n=a*b;
- while(n!=0)
- {
- A=n%10;
- n=n/10;
- if(A==0&&count==0)
- {
- continue;
- }
- count++;
- printf("%d",A);
- }
- return 0;
- }
C++:
- #include
- using namespace std;
-
- int main() {
- int a, b, n;
- int A, count = 0;
- cin >> a >> b;
- n = a * b;
- while (n != 0) {
- A = n % 10;
- n = n / 10;
- if (A == 0 && count == 0) {
- continue;
- }
- count++;
- cout << A;
- }
- return 0;
- }
Java:
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- Scanner scanner = new Scanner(System.in);
- int a = scanner.nextInt();
- int b = scanner.nextInt();
- int n = a * b;
- int A, count = 0;
- while (n != 0) {
- A = n % 10;
- n = n / 10;
- if (A == 0 && count == 0) {
- continue;
- }
- count++;
- System.out.print(A);
- }
- }
- }
Python:
- a, b = map(int, input().split())
- n = a * b
- count = 0
-
- while n != 0:
- A = n % 10
- n = n // 10
- if A == 0 and count == 0:
- continue
- count += 1
- print(A, end='')