思路:

ACcode:
-
- #include<bits/stdc++.h>
- using namespace std;
- #define int long long
- const int N=1e5+10;
- int n,a[N],ans;
- void solve() {
- cin>>n;
- for(int i=1;i<=n;i++)cin>>a[i];
-
- int ans=0;
- for(int i=1;i<=n;i++){
- if(a[i]>a[i-1]) ans+=a[i]-a[i-1];
- }
- cout<<ans<<"\n";
- }
- signed main() {
- ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
- int t=1;
- //cin>>t;
- while(t--) {
- solve();
- }
- return 0;
- }
-
-
-
-
over~