1.读存储器
LDR R1,[R2]
2.写存储器
1.读存储器
data =*ADDR
2.写存储器
*ADDR = data
实现LED2-LED5的流水灯:
代打如下
- #include"exynos_4412.h"
- int main(int argc, const char *argv[])
- {
- //LED2 的28-31位变为0001,其余不变
- GPX2.CON = GPX2.CON & (~(0xF<<28))|(0x1<<28);
- //LED3 的di [0-3]位变为0001,其余不变
- GPX1.CON = GPX1.CON & (~(0xF<<28))|(0x1);
- //LED5 的20位变为1,其余不变
- GPF3.CON = GPF3.CON & (~(0xF<<20))|(0x1<<20);
- //LED4 的20位变为1,其余不变
- GPF3.CON = GPF3.CON & (~(0xF<<16))|(0x1<<16);
-
-
-
-
-
- while(1)
- {
- /*LED2点亮*/
- GPX2.DAT = GPX2.DAT | (1<<7);
- /*延时*/
- Delay(1000000);
- /*熄灭*/
- GPX2.DAT = GPX2.DAT & (~(1<<7));
- Delay(1000000);
-
- /*LED3点亮与熄灭*/
- GPX1.DAT = GPX2.DAT | 1;
-
- Delay(1000000);
-
- GPX1.DAT = GPX1.DAT & (~1);
-
- Delay(1000000);
- /*LED4点亮与熄灭*/
-
- GPF3.DAT = GPF3.DAT | (1<<4);
- Delay(1000000);
- GPF3.DAT = GPF3.DAT & (~(1<<4));
- Delay(1000000);
-
-
- /*LED5点亮与熄灭*/
- GPF3.DAT = GPF3.DAT | (1<<5);
- Delay(1000000);
- GPF3.DAT = GPF3.DAT & (~(1<<5));
- Delay(1000000);
-
-
-
- }
- return 0;
- }