\right.
H={θ,360−G,B≤GB≥G 其中,
θ
=
a
r
c
c
o
s
{
1
2
[
(
R
−
G
)
+
(
R
−
B
)
]
[
(
R
−
G
)
2
+
(
R
−
B
)
(
G
−
B
)
]
1
/
2
}
\theta=arccos\{\frac{\frac{1}{2}[(R-G)+(R-B)]}{[(R-G)^2+(R-B)(G-B)]^{1/2}}\}
θ=arccos{[(R−G)2+(R−B)(G−B)]1/221[(R−G)+(R−B)]}
S
=
1
−
3
(
R
+
G
+
B
)
[
m
i
n
R
,
G
,
B
)
]
S=1-\frac{3}{(R+G+B)}[minR,G,B)]
S=1−(R+G+B)3[minR,G,B)]
I
=
1
3
(
R
+
G
+
B
)
I=\frac{1}{3}(R+G+B)
I=31(R+G+B)
HSI -> RGB:
若在 RG 扇区内(
0
∘
≤
H
<
12
0
∘
0^\circ\leq H<120^\circ
0∘≤H<120∘)
B
=
I
(
1
−
S
)
R
=
I
[
1
+
S
c
o
s
H
c
o
s
(
6
0
∘
−
H
)
]
G
=
3
I
−
(
R
+
B
)
若在 GB 扇区内(
12
0
∘
≤
H
<
24
0
∘
120^\circ\leq H<240^\circ
120∘≤H<240∘)
H
=
H
−
12
0
∘
R
=
I
(
1
−
S
)
G
=
I
[
1
+
S
c
o
s
H
c
o
s
(
6
0
∘
−
H
)
]
B
=
3
I
−
(
R
+
B
)
若在 RB 扇区内(
24
0
∘
≤
H
<
36
0
∘
240^\circ\leq H<360^\circ
240∘≤H<360∘)
H
=
H
−
24
0
∘
G
=
I
(
1
−
S
)
B
=
I
[
1
+
S
c
o
s
H
c
o
s
(
6
0
∘
−
H
)
]
R
=
3
I
−
(
R
+
B
)
欧式距离(轨迹是球体):
D
(
z
,
a
)
=
∣
∣
z
−
a
∣
∣
D(z,a)=||z-a||
D(z,a)=∣∣z−a∣∣
马氏距离(轨迹是椭球体):
D
(
z
,
a
)
=
[
(
z
−
a
)
T
C
−
1
(
z
−
a
)
]
1
2
D(z,a)=[(z-a)^TC^{-1}(z-a)]^{\frac{1}{2}}
D(z,a)=[(z−a)TC−1(z−a)]21
边界盒(避免开方运算):
D
(
z
,
a
)
=
z
−
a
D(z,a)=z-a
D(z,a)=z−a
彩色边缘检测
单独处理 RGB 三个分量的梯度图像再合成可能会导致错误的结果
对于标量函数,梯度是坐标点指向 f 的最大变化率的方向
u
=
∂
R
∂
x
r
+
∂
G
∂
x
g
+
∂
B
∂
x
b
,
v
=
∂
R
∂
y
r
+
∂
G
∂
y
g
+
∂
B
∂
y
b
u=\frac{\partial R}{\partial x}r+\frac{\partial G}{\partial x}g+\frac{\partial B}{\partial x}b, v=\frac{\partial R}{\partial y}r+\frac{\partial G}{\partial y}g+\frac{\partial B}{\partial y}b
u=∂x∂Rr+∂x∂Gg+∂x∂Bb,v=∂y∂Rr+∂y∂Gg+∂y∂Bb
g
x
x
=
u
⋅
u
=
u
T
u
=
∣
∂
R
∂
x
∣
2
+
∣
∂
G
∂
x
∣
2
+
∣
∂
B
∂
x
∣
2
g
y
y
=
v
⋅
v
=
v
T
v
=
∣
∂
R
∂
y
∣
2
+
∣
∂
G
∂
y
∣
2
+
∣
∂
B
∂
y
∣
2
g
x
y
=
u
⋅
v
=
u
T
v
=
∂
R
∂
x
∂
R
∂
y
+
∂
G
∂
x
∂
G
∂
y
+
∂
B
∂
x
∂
B
∂
y
可以证明
c
(
x
,
y
)
c(x, y)
c(x,y) 方向上的最大变化率的值由以下角度给出
θ
(
x
,
y
)
=
1
2
a
r
c
t
a
n
[
2
g
x
y
g
x
x
−
g
y
y
]
\theta(x,y)=\frac{1}{2}arctan[\frac{2g_{xy}}{g_{xx}-g_{yy}}]
θ(x,y)=21arctan[gxx−gyy2gxy]
且在该角度方向上的变化率的值由下式给出
F
θ
(
x
,
y
)
=
{
1
2
[
(
g
x
x
+
g
y
y
+
)
+
(
g
x
x
−
g
y
y
)
c
o
s
2
θ
(
x
,
y
)
+
2
g
x
y
s
i
n
2
θ
(
x
,
y
)
]
}
1
2
F_{\theta}(x,y)=\{\frac{1}{2}[(g_{xx}+g_{yy}+)+(g_{xx}-g_{yy})cos2\theta(x,y)+2g_{xy}sin2\theta(x,y)]\}^{\frac{1}{2}}
Fθ(x,y)={21[(gxx+gyy+)+(gxx−gyy)cos2θ(x,y)+2gxysin2θ(x,y)]}21