目录
问题 B: Sum of the matrix diagonals
乐
我刚写完第二题看倒数三四道题都有人过了
直接倒序开题
果然后面的都是水题
最模拟那个应该就是求根公式了
- s=input()
- for i in s:
- print(i,end=" ")
题意是求对角线元素和
看半天没看明白
- h=[]
- w=[]
- for i in range(0,3):
- s=input().split()
- h.append(int(s[i]))
- w.append(int(s[2-i]))
- print(sum(h), sum(w))
- a=int(input())
- fl=0
- for i in range(2,a):
- if(a%i==0):
- print("not prime")
- fl=1
- break
- if fl==0:
- print("prime")
- a=list(map(int,input().split()))
- a.sort()
- for i in range(0,len(a)):
- print(a[i])
- a1=input()
- print(a1[::-1])
求根公式写就好了
- a,b,c=map(int,input().split())
- dt=b*b-4*a*c
- import math
- if dt>=0:
- n=math.sqrt(dt)
- x1=(n-b)/2*a
- x2=(-n-b)/2*a
- print("x1=%.3f x2=%.3f"%(x1,x2))
- else:
- k=math.sqrt(-dt)
- aa=(-b/(2*a))
- bb=k/(2*a)
- print("x1=%.3f+%.3fi x2=%.3f-%.3fi"%(aa,bb,aa,bb))
- a1=input()
- a2=input()
- a3=input()
- for i in range(0,5,2):
- print(a1[i],end=' ')
- print(a2[i],end=' ')
- print(a3[i])
- a1=input()
- a2=input()
- a3=input()
- for i in range(0,5,2):
- print(a1[i],end=' ')
- print(a2[i],end=' ')
- print(a3[i])
- a=input()
- b=input()
- print(a+b)
- a=input()
- for i in a:
- if i in "aeiou":
- print(i,end="")