• 1028 List Sorting


    Excel can sort records according to any column. Now you are supposed to imitate this function.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains two integers N (≤105) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

    Output Specification:

    For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.


    Sample Input 1:

    1. 3 1
    2. 000007 James 85
    3. 000010 Amy 90
    4. 000001 Zoe 60

    Sample Output 1:

    1. 000001 Zoe 60
    2. 000007 James 85
    3. 000010 Amy 90

    Sample Input 2:

    1. 4 2
    2. 000007 James 85
    3. 000010 Amy 90
    4. 000001 Zoe 60
    5. 000002 James 98

    Sample Output 2:

    1. 000010 Amy 90
    2. 000002 James 98
    3. 000007 James 85
    4. 000001 Zoe 60

    Sample Input 3:

    1. 4 3
    2. 000007 James 85
    3. 000010 Amy 90
    4. 000001 Zoe 60
    5. 000002 James 9

    Sample Output 3:

    1. 000002 James 9
    2. 000001 Zoe 60
    3. 000007 James 85
    4. 000010 Amy 90

    题目大意

    给你N个学生的 ID name score,根据输入的排序要求key进行排序

    1. 根据ID升序

    2. 根据名字升序,注意名字相同时按分数降序

    3. 根据分数升序,注意分数相同时按ID升序


    思路

    建立学生结构体,然后sort排序


    C/C++ 

    1. #include
    2. using namespace std;
    3. struct Student{
    4. string id,name;
    5. int score;
    6. }s;
    7. vector all;
    8. int N,key;
    9. bool cmp(const Student& x,const Student& y ){
    10. if(key==1) return x.id < y.id;
    11. if(key==2) return x.name != y.name ? x.name y.score;
    12. return x.score != y.score ? x.score < y.score : x.id < y.id;
    13. }
    14. int main()
    15. {
    16. cin >> N >> key;
    17. while (N--){
    18. cin >> s.id >> s.name >> s.score;
    19. all.push_back(s);
    20. }
    21. sort(all.begin(),all.end(),cmp);
    22. for(const Student& x:all){
    23. cout << x.id << " " << x.name << " " << x.score << endl;
    24. }
    25. return 0;
    26. }

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  • 原文地址:https://blog.csdn.net/daybreak_alonely/article/details/127712946