2. 用欧拉方法和龙格-库塔方法解决简化的实际问题。





(1)
- function dv = fun(v,~)
- weight=527.436*0.4536*9.8;%单位N,实际上11bf=4.44822162N,这里11bf=4.44528N
- buoyancy=470.327*0.4536*9.8;%单位N
- K=0.08*0.4536*9.8/0.3048;%阻力比例系数
- g=9.8;
- dv = g*(weight-buoyancy)/weight-K*g*v/weight;
- end
- function dy= fun2(v,~)
- weight=527.436*0.4536*9.8;%单位N,实际上11bf=4.44822162N,这里11bf=4.44528N
- buoyancy=470.327*0.4536*9.8;%单位N
- K=0.08*0.4536*9.8/0.3048;%阻力比例系数
- g=9.8;
- dy = (v*(weight/g))/(weight-buoyancy-K*v);
- end
-
- [v,t]=ode45('