python实现矩阵转置

使用列表推导式实现矩阵转置

matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
print([[row[i] for row in matrix]for i in range(4)])
1
2

使用内置函数来实现矩阵转置

matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
print(list(map(list, zip(*matrix))))
1
2

使用二重循环实现矩阵转置

matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
x = []
for i in range(len(matrix[0])):
    y = []
    for j in range(len(matrix)):
        y.append(matrix[j][i])
    x.append(y)
print(x)
1
2
3
4
5
6
7
8