单链表排序

单链表排序

问题

对一个带头结点的单链表进行排序，使其按key值递增的顺序进行就地排序。

代码

#include 
#include 
#include 

typedef struct LNode {
    int key;
    struct LNode *next;
} LNode, *LinkList;

bool InitList(LinkList &L) {
    L = (LNode *) malloc(sizeof(LNode));
    if (L == NULL) {
        return false;
    }
    L->next = NULL;
    return true;
}

bool Empty(LinkList &L) {
    return (L->next == NULL);
}

bool ListInsert(LinkList &L, int i, int e) {
    if (i < 1)
        return false;
    LNode *p;
    int j = 0;
    p = L;
    while (p != NULL && j < i - 1) {
        p = p->next;
        j++;
    }
    if (p == NULL) {
        return false;
    }
    LNode *s = (LNode *) malloc(sizeof(LNode));
    s->key = e;
    s->next = p->next;
    p->next = s;
    return true;
}

void PrintList(LinkList L) {
    LNode *p = L->next;
    while (p != NULL) {
        printf("%d ", p->key);
        p = p->next;
    }
    printf("\n");
}

void ListSort(LinkList &L) {
    LNode *p, *m, *q;
    p = (LNode *) malloc(sizeof(LNode));
    m = (LNode *) malloc(sizeof(LNode));
    q = (LNode *) malloc(sizeof(LNode));
    m = L->next;
    while (m != NULL) {
        p = m;
        q = p->next;
        while (q != NULL) {
            int temp;
            if (p->key > q->key) {
                temp = p->key;
                p->key = q->key;
                q->key = temp;
                PrintList(L);
            }
            q = q->next;
        }
        m = m->next;
    }
}

int main() {
    LinkList L;
    InitList(L);
    int arr[20] = {1, 4, 6, 8, 2, 3, 5, 7, 9, 0, 10, 11, 15, 14, 13, 12};
//    int arr[20] = {15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0};

    for (int i = 0; i < 16; i++) {
        printf("%d ", arr[i]);
    }
    printf("\n");
    for (int i = 1; i <= 16; i++) {
        ListInsert(L, i, arr[i - 1]);
    }

    ListSort(L);
    PrintList(L);
    return 0;
}


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结果